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Find the general solution of \[cos x + \sqrt{3}sin x = \sqrt{2}\]
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\[\frac{1}{2}\cos x + \frac{\sqrt{3}}{2}\sin x = \frac{\sqrt{2}}{2}\]\[\cos \frac{\pi}{3}\times\cos x + \sin \frac{\pi}{3}\times\sin x = \frac{\sqrt{2}}{2}\]
\[sin (x + pie/6) = \frac{1}{\sqrt{2}}\]
be carefull\[\cos(x + \frac{\pi}{3}) = \cos \frac{\pi}{4} \]
sorry i must be carefull too :)\[\cos(x - \frac{\pi}{3}) = \cos \frac{\pi}{4}\]
Yes...i got it thx.....
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