how about this one 101, 12, 11, 10, ....
If it was not for the 101, it'd definitely have been 9.
yup
hint: its not a 'conventional' series with a formula for nth term
I think I know this...
is it 5 ? my quess
guess *
in different bases :)
so it should be 1 I believe
yes and the next one is 5 also then 5,5,5.......
yey .... but I only guessed I will like to hear the right soln
101 = 5 in base 2 12 = 5 in base 3 11 = 5 in base 4 10 = 5 in base 5 5 = 5 in base 6
i think asnaseer has it
typo from me above 5 NOT 1
right!
5,5,5,5,...
*nice question, i was thinking of different bases but still could not get this one.
jimmyrep gave me this one
\[\large -\frac{\left(\frac{89(n-1.5)}{|n-1.5|}+\frac{(n-2.5)}{|n-2.5|}+\frac{n-3.5}{|n-3.5|}+5\frac{n-4.5}{|n-4.5|}+106\frac{n-5.5}{|n-5.5|}\right)}{2}\] i can get; ...,5,-101,-101,-101 :)
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