Dimensional Analysis problem: vf (final velocity) = vi (initial velocity) x t + a v = meters/second t = seconds a = meters/second squared
the above equation is dimentsionly incorrect.........the dimension of each term must be same......but in above equation the dimensions of all three terms is different... the correct equation is vf= vi+ at
Can you please show me each step in order to understand the problem? believed it to be invalid, however, I don't know that my work successfully shows that I'm understanding the concept. Thanks.
the dimension of vf is m/s....so the dimension of the terms right to the equal to sign must be m/s.....but the dimension of vt is meters as ( meters/second X second )...and dimension of a is m/s^2
Can you work out m/s = 2m/s squared?
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