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Simplify k^k/(k+1)^(k+1)
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meaning \[(k)^{k}/(k+1)^{k+1}\]
( k +1) ^ (k +1) = ( k +1) ^ k * ( k + 1)
yep i agree with that, thats the bottom only what about the top
thats my issue, im trying to simplify an infinite series using the ratio test and cant figure out how to simplify this part to make stuff cancel
It's not possible to simplify, since no divisor of \(k\) will divide \(k+1\).
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(Or the other way around)
But... I will say that using the ratio test, the series converges absolutely, since \(\frac{k^k}{(k+1)^{k+1}}<\frac{k^k}{k^{k+1}}\) whose limit is actually zero. But, I don't know if you meant it the other way around since it is: \[ \lim_{n\to\infty}\left|\frac{a_{n+1}}{a_n}\right| \]
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