Solve the following equation, giving the exact solutions which lie in [0, 2π). (Enter your answers as a comma-separated list.) sin(2x) = sin(x)
I thought the answers were\[ x=0,\pi/3,5\pi/3 \]
I'm getting cos(x) = 1/2.
your dividing when you should subtract and factor.
2sinxcosx-sinx=0--> sinx(2cosx-1)=0
Why would you do that?
because if you divide then you are losing x=0 which works.
Ah, true. Then it looks like you did everything fine then.
but i am getting incorrect.
Might it be how you're entering your solution? Maybe leave out the "x=" part and just put the list of numbers.
i did that originally
becuase there is and "x=" in front of the box.
Hmm, all those solutions work, they are in the correct interval...
Oh, we're missing π!
jinks
i thought that at the same time
lol
sin(2π)=sin(π)=0. Gah, I feel even more embarrassed than I did before.
It's been too long since I've done the trig.
thanks a bunch! I appreciate it. We had a brainstorm going and it was good.
Have a great weekend!
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