How long does it take for the plane to stop with this acceleration? Answer in units of s
\[v^2 = u^2 + 2as\]I see only one equation of motion with \(s\).
Anyway, what is the acceleration?
not sure if he means units of "seconds"
africanboy you need to provide velocity and acceleration(values)
The question is incomplete :|
i will agree with that
A plane landing on a small tropical island has just 64 m of runway on which to stop. If its initial speed is 66 m/s, what is the maximum acceleration of the plane during landing, assuming it to be constant? Answer in units of m/s How long does it take for the plane to stop with this acceleration? Answer in units of s
Fundamental kinematics equations to solve for time: \[x=x_0+v_0t+\frac{1}{2}at^2, \space v=at\]
The equation Parth provided is a combination of the above two and can be used to find the acceleration.
i just need help with the second part
do you already know the acceleration?
Then use the first fundamental kinematics equation.
It's a quadratic equation in t, and you can use the quadratic formula to solve.
the acceleration is -34.03125
Actually, I think the second one will work too...
0=1/2(-34.03125)t^2+66t-64 solve for t
yes, the second equation, v=at, works too and is a lot easier.
thanks this is my first time using this website
I got 64/33 s. How about you?
Though, you'll probably want to round that to 2 significant figures to be honest about the uncertainty.
sorry still cant find t
\[\Delta v = a \cdot t\] Is the simplest way to get it. You have the acceleration, a, and the change in velocity is (0m/s - 66m/s) = -66m/s, so use that info to solve for t.
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