A.) A woman spent $250 for jeans and a ski jacket. If she spent y dollars for the ski jacket, represent the amount she spent for the jeans. B.) The width of a rectangle is x centimeters. Represent the lenghth of the rectangle if it exceeds twice the width by 3 centimeters
Since the sum of the two values must equal 250, then we have: \[ j+y=250 \]Solving for \(j\) we get: \[ j=250-y \]Since: \[ (250-y)+y=250 \]Then, the amount spent on jeans is: \[ 250-y \]And so, we're done.
I dont really get how you did that
i feel so stupid
i get it up to Since: (250−y)+y=250 Then, the amount spent on jeans is: 250−y And so, we're done.
It's all right, here: So we know we have the two values, which must add up to 250. Using that, we get: \[ j+y=250 \]Subtract y from both sides: \[ j+y-y=250-y\implies\\ j+0=250-y\implies\\ j=250-y \]So, the price for the jeans is \(250-y\), where \(y\) is the price for the jacket.
Oh, that's just to show that the expressions are equal, it's an added detail, not really all that important.
thanks so muchh!!!!!!!!! can you also help me with b? its fine if you cant but thanks again
Sure, sorry I was out eating. If the length exceeds twice the width (which we call \(x\)) by three, then: \[ 2x+3=l \]
thanks thats what i got
Nice, and sure thing.
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