Question

An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x direction when its x coordinate is 3.09 cm. If its x coordinate 2.45 s later is −5.00 cm, what is its acceleration?

Answer 1

so you have
\[v_1 = 14.0 \; cm/s\]
\[x_1 = 3.09 \; cm\]
\[x_2 = -5.00 \; cm\]
\[t = 2.45 \; s\]

Answer 2

looks like you have to use the formula \[x_2 - x_1 = v_1 t + \frac{at^2}2\]

Answer 3

does that help?

Answer 4

yeah it does
alot

Answer 5

thank you bro

Answer 6

welcome