Question

Help please

Answer 1

ok just do this:
324^(1/4)*x^(16/4)*y^(21/4)
and simplify

Answer 2

\(324=4\times 3^4\) so you have
\[\sqrt[4]{3^4\times 4x^{16}y^{21}}\]
4 goes in to 4 one time, the 3 comes out
4 goesin to 16 4 times, \(x^4\) comes out
4 goes in to 21 5 times with a remainder of 1 so \(y^5\) comes out, and a \(y\) stays in, along with the 4
you get
\[3x^4y^5\sqrt[4]{4y}\]

Answer 3

@satellite73 can I ride you?

Answer 4

lol

Answer 5

Lol, thats the final answer? o.0

Answer 6

yes lol is indeed the final answer

Answer 7

ride away ;)