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How many uranium atoms are there in 7.1 g of pure uranium? The mass of one uranium atom is 4 × 10^−26kg.
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using your info:\[7.1g\frac{1 atom}{4x10^{-26}kg}\frac{1 kg}{1000 g}\]
Still confused... what am I supposed to do with that?
They are conversion units... if the units cancel, you usually get the right answer, but it tells you how to multiply or divide to get the answer (if the units work out). If you look at it... kg cancels with kg and g cancels with g... leaving atoms in the numerator. To get the number... take 7.1 divided by 4x10^-26 then divide again by 1000.
ohhh okay that makes sense! thanks
You're welcome. :)
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