Question

factor: 2p^4-32q^4

Answer 1

common factor first

Answer 2

first take 2 common to get \(2(p^4-16q^4)\)
then note 16=2^4
so u get
\(2(p^4-(2q)^4)\)
now use a^2-b^2=(a+b)(a-b)

Answer 3

can u @Mberdeja501 ?

Answer 4

I don't understand how to plug the numbers in... @hartnn

Answer 5

divide out 2 first to get what @hartnn got in his first line...
then use difference of squares for the next step

Answer 6

don't stop because of me @hartnn

Answer 7

ok so then i get 2((p^2-2q^2)(p^2+q^2))? @EulerGroupie ?

Answer 8

there are no numbers to plug in,
write \((p^4-(2q)^4)=(p^2)^2-((2q)^2)^2\)
now can u use a^2-b^2 formula?

Answer 9

Yes!

Answer 10

yes thats right
now use a^2-b^2 again on p^2-(2q)^2

Answer 11

Oops kinda

Answer 12

yeah i missed the 2.. ha

Answer 13

Those 2's should be 4's

Answer 14

2(p^2-4q^2)(p^2+4q^2)

Answer 15

Then you factor out something right? @EulerGroupie

Answer 16

+ to be accurate in 2nd factor.

Answer 17

\[2(p ^{2}-4q ^{2})(p ^{2}+4q ^{2})\]to be prettier... then there is another difference of squares in there. Do you see it?

Answer 18

you are on it!

Answer 19

yes!!! :D awesome. Thanks

Answer 20

No problem... @hartnn is my hero... I feel funny interupting. Sorry buddy.

Answer 21

actually ,my net is not letting me comment, thats why delayed replies.....good that euler took over.

Answer 22

when i submit that answer it says its incorrect..

Answer 23

did you find the second difference of squares?

Answer 24

that\[p ^{2}-4q ^{2}\]has another step

Answer 25

ohhhh ok.. from there thats when you take out something right?

Answer 26

not a common factor... another difference of squares\[p ^{2}-4q ^{2}=(p-2q)(p+2q)\]now put it all together

Answer 27

show me... then I'll verify before you input to program

Answer 28

ok so i get 2((p-2q)(p+2q)((p+2q)(p+2q))) right?

Answer 29

no... there is no sum of square... keep the sum as it was... with the squares in it

Answer 30

the difference factors out more... the one with the plus sign does not.

Answer 31

2((p-2q)(p+2q))(p^2+4q^2)?

Answer 32

Yes! no need for the extra parethesis though. just 2( )( )( ) and you are good!

Answer 33

2(p^2+4q^2). cause they cancel out right?

Answer 34

nope, it was better before... no cancellation

Answer 35

damn haha..

Answer 36

Yeah, they would foil... not cancel

Answer 37

I'm with ya' til your program takes it... let me know.

Answer 38

thanks for being patient with me and explaining it so many times :)

Answer 39

I understand, we are not done til credit is issued.

Answer 40

the program took the answer.

Answer 41

woof!