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Mathematics 19 Online
OpenStudy (anonymous):

Help Please. difference quotient question

OpenStudy (anonymous):

7/x using \[f(x+h)-f(x)/h\]

OpenStudy (unklerhaukus):

\[\frac{f(x+h)-f(x)}h\]

OpenStudy (anonymous):

yea that

OpenStudy (anonymous):

i got as far as this |dw:1347171689308:dw|

OpenStudy (anonymous):

find a CD in the numerator \[\frac{ \frac{ 7 }{ x+h } -\frac{ 7 }{ x } }{ h }\]

OpenStudy (anonymous):

\[\frac{ \frac{ 7(x+h)-7x }{ x(x+h) } }{ h }\]

OpenStudy (anonymous):

i got the answer as -7

OpenStudy (anonymous):

whoops signs need to be swapped

OpenStudy (anonymous):

\[\frac{ \frac{ -7(x+h)+7x }{ x(x+h) } }{ h }\]

OpenStudy (anonymous):

simplify the numerator

OpenStudy (anonymous):

\[-7(x+h)+7x =?\]

OpenStudy (anonymous):

-7h then divide by the h and you get -7 right?

OpenStudy (anonymous):

yep:) \[\frac{ \frac{ -7h }{ x(x+h) } }{ h } = \frac{ -7h }{ h*x(x+h) }\]

OpenStudy (anonymous):

\[\frac{ -7 }{ x(x+h) }\]

OpenStudy (anonymous):

now you can take the limit without a problem...

OpenStudy (anonymous):

so the final answer would be |dw:1347172212702:dw|

OpenStudy (anonymous):

I guess... aren't you supposed to be taking the limit as h->0 ?

OpenStudy (anonymous):

idk really the instructions just say to simplify

OpenStudy (anonymous):

I guess you're fine then

OpenStudy (anonymous):

thanks alot your a great help :)

OpenStudy (anonymous):

sure:)

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