Mathematics
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OpenStudy (anonymous):
Help Please.
difference quotient question
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OpenStudy (anonymous):
7/x using \[f(x+h)-f(x)/h\]
OpenStudy (unklerhaukus):
\[\frac{f(x+h)-f(x)}h\]
OpenStudy (anonymous):
yea that
OpenStudy (anonymous):
i got as far as this
|dw:1347171689308:dw|
OpenStudy (anonymous):
find a CD in the numerator
\[\frac{ \frac{ 7 }{ x+h } -\frac{ 7 }{ x } }{ h }\]
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OpenStudy (anonymous):
\[\frac{ \frac{ 7(x+h)-7x }{ x(x+h) } }{ h }\]
OpenStudy (anonymous):
i got the answer as -7
OpenStudy (anonymous):
whoops signs need to be swapped
OpenStudy (anonymous):
\[\frac{ \frac{ -7(x+h)+7x }{ x(x+h) } }{ h }\]
OpenStudy (anonymous):
simplify the numerator
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OpenStudy (anonymous):
\[-7(x+h)+7x =?\]
OpenStudy (anonymous):
-7h
then divide by the h and you get -7 right?
OpenStudy (anonymous):
yep:)
\[\frac{ \frac{ -7h }{ x(x+h) } }{ h } = \frac{ -7h }{ h*x(x+h) }\]
OpenStudy (anonymous):
\[\frac{ -7 }{ x(x+h) }\]
OpenStudy (anonymous):
now you can take the limit without a problem...
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OpenStudy (anonymous):
so the final answer would be |dw:1347172212702:dw|
OpenStudy (anonymous):
I guess... aren't you supposed to be taking the limit as h->0 ?
OpenStudy (anonymous):
idk really the instructions just say to simplify
OpenStudy (anonymous):
I guess you're fine then
OpenStudy (anonymous):
thanks alot your a great help :)
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OpenStudy (anonymous):
sure:)