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What is the distance between P(–4, 3) and Q(6, 1)?
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Use the distance formula., if you know it!
\[distance = {\sqrt(x_2 - x_1)^2 + (y_2 - y_1)^2}\]
\[d = \sqrt(x^2 - x^1)^2 + (y^2 - y^1)^2\]
Yeah, but 2 and 1 are subs... not exponents!
\[d = \sqrt(3 - 1)^2 + (-4 + 6)^2?\]
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\[= \sqrt(2)^2 + (10)^2\]
\[\sqrt(4 + 100) = \sqrt(104) \approx \]
Yes
And rounded to the nearest tenth is approximately 10.2? Thanks @ParthKohli ! :)
Actually you can express it in radical form, since that's more accurate!
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104|2 52|2 26|2 13|13 -------
\[\sqrt{104 } \implies \sqrt{2 \times 2 \times 2 \times 13} \implies 2\sqrt{26}\]
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