Question

prove trig identity...

Answer 1

\[\tan \theta=\frac{ \sin 2\theta }{ 1+\cos2\theta }\]

Answer 2

write sin 2theta = 2sin theta cos theta
and 1+cos 2 theta = 2 cos^2 theta.

Answer 3

We already know that,\[\tan = {\sin \over \cos}\]and if you try to simplify\[2\sin\theta \cos\theta \over 2\cos^2\theta\], then you get \(\large{\sin\theta\over \cos\theta}\)

Answer 4

Ahh. ok thanks

Answer 5

You're welcome :)