0.142871428714287.... convert this into rational number
ok so I know this but I want the answer from some one else.... (any user)
I have a confusion regarding this method... I will post after some one solves this
\[10^5a=14287.1428714287...\]\[(10^5a-a)=14287\]\[a=\frac{14287}{99999}\]
that is the same method I would have used :)
Ok so mukushla has a right process ...
Now : my question is 0.9999999.... convert this into rational number
.99999... = 1
right but why so?
because it is infinitely long series of 9's after the decimal point - do you want a proof of this?
0.99999... = x 10x = 9.999... 10x-x = 9.999.. - 0.999... = 0 9x = 9 x-9/9 = 1
there are many proofd
0.9999...=x 10x=9.999... 10x-x=9.999...-.9999=9 9x=9 x=1
yes asnaseer sir... I have to do that proof in tomorrow's exam Though must say that "in the question we are provided to discuss with your teacher"
e.g. 1/3 = 0.3333333... therefore 3(1/3) = 0.9999... therefore 1 = 0.999...
Turing take a look at the question above
the trick is to find the point where the decimal starts repeating and miltiply first to get the decimal at the beginning of the part that repeats, then the get the decimal at the end of the repeating part
agent47 ... check my comments
huh? I'm lost
0.3333... should be 0 (rounding off) x = 0.333... 10x = 3.333 10x-x = 3.333... - 0.333... 9x = 3 x =3/9 = 1/3
since 0.999 = 1 (rounded off) so why not then 0.333... = 0 ?
rounding off is a different process - it does not produce identities
it is a wat of getting approximations to a given number
*way
why 0.333.... is 1/3 and why 0.999... is 1 ? @asnaseer and @TuringTest is this trick of which you both are referring to ? 0.3 = 3/10 0.33... = 1/3 3(0.33...) =3(1/3) 0.999 ..= 1 "hence proved?"
my method is different than asnaseesr's more common sense approach. Though I think his will be tricky from more ugly numbers\[x=4.56\overline{248}\]first multiply to get the decimal at the beginning of the repeating part\[100x=456.\overline{248}\]then again to get it after the repeating part\[100000x=456248.\overline{248}\]now subtract the two\[100000x-100x=456248.\cancel{\overline{248}}-456.\cancel{\overline{248}}\]\[999900x=4455972\]
I think asking why 0.333...=1/3 is equivalent to asking why is 1=1
:P I didn't think so of my question .... @asnaseer ... I got it now... thanks @TuringTest and @asnaseer
yw :)
welcome
Though "if" I will ask that prove 1 = 1 .... what will you think of me? and of your answer?
and BTW @TuringTest - I use the same method as you and @mukushla did, I showed that there are also other ways of proving these identities :)
yes I noticed, and appreciated your more down-to-earth approach :)
If I recall correctly, the proof of 1=1 is not trivial :)
I am lucky to have you both answering my question.... thanks anjum and max.. again but I will ask again "Though "if" I will ask that prove 1 = 1 .... what will you think of me? and of your answer? "
ok so what's your opinion max.?
asnaseer seems to know more about that than I I would have said it's trivial...
it seems more axiomatic to me peano's first: 1 is a number
agreed.
not sure what theorem is required to convince someone that a number is equal to itself, but that would complete the proof
reflexivity I guess
"Euclid's axiom"
sorry - I confused it with the proof of 1+1=2 which is here: http://humor.beecy.net/misc/principia/
1 + 1 = 2 1 = 2-1 =1 hence proved... :P thanks anjum
:D
haha the russel/whitehead principia does not think that proof is sufficient @mathslover I think Russel would call it a circular argument
:P
he called most things circular arguments - I guess he enjoyed eating \(\pi\) too much :D
:)
apple pi ? :P
peeps ... m i wasting my time for exams? "yes" so thanks guys bbye
"closed"
wow. look at the number of the math lovers here
So, actually 0.999999999... is not close to 1.......... its equal to 1?
@mukushla
yes
Thanx........ I think I got it..
welcome
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