Question

(a+bi)^2=i
What is square(i)
solve geometrically in a complex number plane

Answer 1

squareroot of i

Answer 2

http://www.milefoot.com/math/complex/squarerootofi.htm

this website helps u a lot i think

Answer 3

u can expand the square
\[ \large i=(a+ib)^2=a^2+2abi-b^2=(a^2-b^2)+2abi \]

Answer 4

from this
\[ \large a^2-b^2=0 \]
and
\[ \large 2ab=1 \]

Answer 5

yeah but we need a geometrical solution

Answer 6

I need to setch how I did it

Answer 7

or can I just answer squareroot of 2 / ?

Answer 8

well the equations give us \(a=b\) and \(a=1/\sqrt{2}\)

Answer 9

I dont understand....

Answer 10

what?

Answer 11

nothing now I see

Answer 12

Thanks!

Answer 13

but ... i have no idea how to do this "geometrically".

Answer 14

neither have I T_T

Answer 15

I can see how to do it algebraic and thats how I will turn it in I guess

Answer 16

maybe if u write the complex number \(z=a+ib\) in trigonometric form. that way u could use a geometric approach.