Question

If 62.7 g N2 react with 23.8 g H2 according to the reaction below, how many grams of ammonia (NH3) can be produced, and how many grams of the excess reactant will be left over?

Unbalanced equation: N2 + H2 → NH3

Be sure to show all of your work.

Answer 1

I would start by balancing that equation.

Answer 2

NH?

Answer 3

you need a balanced chemical equation to solve this type of problem

_N2 + _H2 --> _NH3 fill in the coefficent that would balance this.

Answer 4

3N2+1H2--->1NH3?

Answer 5

Nice try but the goal of doing this is to get the same number of atoms on each side of the arrow. I would start with the hydrogen on both sides.

Answer 6

I don't know

Answer 7

Ok according to the unbalance equation you have

2 hydrogen on the left and 3 hydrogen on the right, what is the smallest number we can multiply each side by to get both sides equal

Answer 8

the 2 by 3 and the 3 by 2

Answer 9

alright, so plug in those and check and see if diong that gives you the proper amount of N on each side. then rewrite the properly balanced equation.

Answer 10

N2 + 3 H2 ----> 2 NH3

Answer 11

ok before we move on do you understand how to do that?

Answer 12

yeah

Answer 13

ok now we need to figure out what the limiting reagent is. So how would we go about finding that do you think?

Answer 14

by how many grams each one has?

Answer 15

well you start with grams and have to change it to moles and we can use stoicometry to figure out how many moles of product we end up with, and convert that back to grams. I would use factor lable if i was you