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how many oxygen atoms are in 4.40g of Al2(so4)3?
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I always hated chemistry...
How many grams will be in 1 mole of that solution?
Solve this first: \[4.40 g Al _{2}(SO _{4})_{3} \times (\frac{ 1 mole Al _{2}(SO _{4})_{3} }{ ? g Al _{2}(SO _{4})_{3} })\]
Then find how many moles of O is in Al2(SO4)3. How much does that amount of moles weigh in grams? Then lastly multiply that number with Avogardo's number to determine how many atoms.
ok thanks!!!
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