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Simplify this
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\[\frac{ a }{ a-1 } + \frac{ 2a }{ a+3 }\]
@Chlorophyll
So common denominator is ...?
Is good.
Start doing Cross Product now: ...
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I did
LCD=(a-1)(a+3)
I got \[a ^{2} + 3 a\] and \[2a ^{2}\]
2a square - 2a *****
Show me your multiplication step:
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Okie, correct !
a x a+3 = \[a ^{2} + 3a\]
and yeah, the other one.
Now, add them!
\[a ^{2} + 3a + 2a ^{2} -2a = 3a ^{2} + a\]
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Correct! Now, plug the common denominator to it!
\[\frac{ 3a ^{2} + a }{ (a-1) + (a+3) }\]
Although that's not in the answers.
Some teacher prefer: a ( 3a + 1) in the numerator!
OH!
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Then it's there.
Thanks :)
No, the denominator is the PRODUCT! ( NOT SUM)
I know.
It's a huge typo, you know :(
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So, everything's fine now?
For this part :P
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