Question

what is the nth term of the sequence 1 2 4 8 16 32?

Answer 1

do u realise that those are powers of 2 ?
so the n'th term is 2^(n-1)
ok?

Answer 2

okk thxxx

Answer 3

Anf how can i prove that

Answer 4

and

Answer 5

ok, put n=1,2,3.....and see whether u get that sequence.......

Answer 6

ok... look at the common ratio by comparing the ratio of terms

\[\frac{T_{2}}{T_{1}} = \frac{T_{3}}{T_{2}} .... \]

Answer 7

this will show that the series is geometric...

A term in a geometric series is

\[T_{n} = a r^{n -1}\]

a = 1st term, r = is the common ratio

just substitute

Answer 8

@campbell_st can you show me for the first term

Answer 9

1st term in the sequence is 1

the sequence is 1, 2, 4, 8, 16, ...

Answer 10

yes

Answer 11

the common ratio is 2...

2/1 = 4/2 = 8/4 = 16/8 .....

so the series is geometric

hope it helps

Answer 12

okkk Thanks alot