Question

2log6(x)=log6(2)+log6(3x+20) solve for x

Answer 1

2log6(x) = log6(x)²
Now, since all the terms have the same base 6, do you know what to do next?

Answer 2

yes.

Answer 3

remove log

Answer 4

the two log laws you need here are as follows:

\[alog(b) = \log(b^a) \text{ , and } \log(a) + \log(b) = \log(ab)\]

Answer 5

Great, could you show the step?

Answer 6

x^2=2+3x+22 and then just solve for x?

Answer 7

not quite, before you get rid of logs you need only one log on each side.

like this:

log(X) = log(Y) implies X =Y

you need to group together the logs on the right using the second rule i posted :)

Answer 8

loga + log b= log(ab)

Answer 9

@nasryn I should have mentioned, please apply the log rule before get rid of log6

Answer 10

a = 2, b = 3x + 20