Question

help

Answer 1

A projectile is thrown upward so that its distance above the ground after t seconds is given by the function h(t) = –16t2 + 704t. After how many seconds does the projectile reach its maximum height?

Answer 2

are you allowed to use calculus? or no?

Answer 3

@sara1234 The projectile would be at the ground at h(t)=0.
-16t^2+96^t=0
First factor out 16t
16t(-t+6)=0
16t=0 and -t+6=0
the projectile is at the ground when
t=0 and t=6

Answer 4

h(t) = –16t^2 + 704t

we need to find the vertex

factor out -16 :

h(t) = -16(t^2 - 44t)

complete the square:
h(t) = -16( (t - 22)^2 - 484)

Answer 5

http://www.youtube.com/watch?v=F-oBYfv_5u4

Answer 6

so after hoe many second does it reach its maximun height

Answer 7

again....are you allowed to use calculus??

Answer 8

h(t) = 16(484 - (t - 22)^2)

so max height is at t = 22

Answer 9

i would recommend the youtube clip i linked to explain further how to find a vertex using completing the square