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OpenStudy (s):
Use separation of variables to solve differential equation: dy/dt=t/((y+1)^1/2)), y(1)=3 ???
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OpenStudy (dumbcow):
use algebra to get "t" terms with dt on one side, and "y" terms with dy on other side
you might try cross-multiplying here
OpenStudy (s):
thanks, I know that step, right now I am stuck with interval part
OpenStudy (anonymous):
interval
integral?
OpenStudy (s):
correct, sorry
OpenStudy (dumbcow):
oh ok, you didn't say so i thought i'd start from beginning :)
im guessing the sqrt(y+1) part
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OpenStudy (anonymous):
if you can't do the 'y' part in your head... use u=y+1 du =dy
\[{ \int\limits_{}^{}} \sqrt{u} du =?\]
OpenStudy (dumbcow):
sqrt is 1/2 power ... just use power rule
OpenStudy (s):
so I get 1/2(y+1)^-1/2=t^2/2 ?
OpenStudy (anonymous):
\[\int\limits_{ }^{ } x ^{n} = \frac{ 1 }{ n+1 } * x ^{n+1}\]
OpenStudy (anonymous):
n here = 1/2
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OpenStudy (s):
i got 2/3(Y+1)^3/2=t^2/2, right?
OpenStudy (dumbcow):
yes ... but don't forget constant "+C" on right side
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