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Mathematics 6 Online
OpenStudy (s):

Use separation of variables to solve differential equation: dy/dt=t/((y+1)^1/2)), y(1)=3 ???

OpenStudy (dumbcow):

use algebra to get "t" terms with dt on one side, and "y" terms with dy on other side you might try cross-multiplying here

OpenStudy (s):

thanks, I know that step, right now I am stuck with interval part

OpenStudy (anonymous):

interval integral?

OpenStudy (s):

correct, sorry

OpenStudy (dumbcow):

oh ok, you didn't say so i thought i'd start from beginning :) im guessing the sqrt(y+1) part

OpenStudy (anonymous):

if you can't do the 'y' part in your head... use u=y+1 du =dy \[{ \int\limits_{}^{}} \sqrt{u} du =?\]

OpenStudy (dumbcow):

sqrt is 1/2 power ... just use power rule

OpenStudy (s):

so I get 1/2(y+1)^-1/2=t^2/2 ?

OpenStudy (anonymous):

\[\int\limits_{ }^{ } x ^{n} = \frac{ 1 }{ n+1 } * x ^{n+1}\]

OpenStudy (anonymous):

n here = 1/2

OpenStudy (s):

i got 2/3(Y+1)^3/2=t^2/2, right?

OpenStudy (dumbcow):

yes ... but don't forget constant "+C" on right side

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