Mathematics
8 Online
OpenStudy (anonymous):
find unit vectors parallel to tangent line to curve y=x^2 at point (2,4)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Can you find f'(x) ?
OpenStudy (anonymous):
-> m = f'(2)
OpenStudy (anonymous):
@dizliz24 Hello...oo
OpenStudy (anonymous):
Sorry, I was working on the problem. I am completely lost on this one. I have no idea where to start
OpenStudy (anonymous):
I forget how to do derivatives
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
f(x) = x^n --> f'(x) = nx ^(n-1)
Now do you remember and start?
OpenStudy (anonymous):
Aha, yes. But how do I relate this to the information that I have available
OpenStudy (anonymous):
f(x) = x^n = x²
Does it look related now?
OpenStudy (anonymous):
Yes, so I have 2x=4, correct? What should be my next step
OpenStudy (anonymous):
Do you understand what's 4?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I am in a toss up. I am not sure if it is y or if it is 2x such that x=2 which is also 4
OpenStudy (anonymous):
Did you read my second post?
OpenStudy (anonymous):
yes. what is m
OpenStudy (anonymous):
y = mx + b
What's m?
OpenStudy (anonymous):
I know that has something to do with slope
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Yes, slope! m is slope!
OpenStudy (anonymous):
Okay, m is the slope. So why does m=f'(2)
OpenStudy (anonymous):
That's how you find slope :)
OpenStudy (anonymous):
That's news to me. Now, what do I do with the slope
OpenStudy (anonymous):
So that's the basic you should memorize!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Then what do you know about unit vector?
OpenStudy (anonymous):
Oh a unit vector is a vector whose length is 1
OpenStudy (anonymous):
How to find magnitude of vector?
OpenStudy (anonymous):
Thats one I am not sure of
OpenStudy (anonymous):
Do you know distance formula?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
d=sqrt((x2-x1)+(y2-y1)
OpenStudy (anonymous):
You miss the square sign (x2-x1)² + ( )²
Great, distance formula to calculate magnitude of vector :)
OpenStudy (anonymous):
Yes, I did.
OpenStudy (anonymous):
How do I use this formula
OpenStudy (anonymous):
Since the unit vector parallel to m = 4 => it's coordinate < 1, 4>
and it's magnitude √1 + 16 = √17
Thus the unit vector is < 1/√17, 4/√17 >
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
Okay but why do we use 1, because it is a unit vector?
OpenStudy (anonymous):
When you divide for magnitude => Unit vector!
OpenStudy (anonymous):
what do you divide
OpenStudy (anonymous):
I don't understand what we are dividing and why we divide
OpenStudy (anonymous):
Then you need to look at your note, notebook about unit vector!
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
I see what you mean. I feel stupid. thank you for your help:)