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1/ sqr root 3t^4 answer should be 3^-1/2 t^-2 but I got 1/ 3^1/2 t^2 so would I just flip it ?
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so are you trying to simplify \[\frac{1}{\sqrt{3t^4}}\]
ok... you're writing it in index form so the index for roots or radicals is \[x^{\frac{1}{2}} = \sqrt {x}\] so you have \[\frac{1}{(3t^4)^{\frac{1}{2}}}\] fractions have negative indices \[x^{-a} = \frac{1}{x^a}\] so you have \[(3t^4)^{-\frac{1}{2}}\] lastly use the power of a power rule \[(x^ay^b)^c = x^{a \times c} y^{b \times c} \] that will give the answer you need
waiiittttt, where did the negative come from? :S
terms in denominators can be written with negative indices
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