Use the limit definition of derivative to find:
3x^2-2x
Show me steps if you can. I just need an answer to confirm that my answer was right.

Question

lgbasallote · Answer

remind me what the definition was...is it $$\huge \lim_{h \rightarrow 0} \frac{f(x+h) - f(x)}h$$

anonymous · Answer

yes

anonymous · Answer

$$f(x+h)=3(x+h)^2-2(x+h)=3(x^2+2xh+h^2)-2x-2h$$
$$=3x^2+6xh+3h^2-2x-2h$$ is a start

anonymous · Answer

nah, I actually done all the steps...just need someone to confirm my answer for me.

anonymous · Answer

from this you subtract $x^2-2x$ so every term without an $h$ in it is gone
then factor out the $h$ and cancel, or else just divide each term by $h$ since there is an $h$ in each one

anonymous · Answer

answer is $6x-2$ next week you will do this in your head in half a second at most

anonymous · Answer

oh, thanks...I was right.

anonymous · Answer

yw