graph V(t)=Cos(t^2-2) in the interval of 0 to pi
-find average velocity
-find the point of maximum velocity and point of minimum velocity
(Plz help i dont know how to do this problem and would appreciate an explanation so i know how to do problems in the future similar to this) (im in physics and nt in calculus yet)

Question

graph V(t)=Cos(t^2-2) in the interval of 0 to pi
-find average velocity
-find the point of maximum velocity and point of minimum velocity
 (Plz help i dont know how to do this problem and would appreciate an explanation so i know how to do problems in the future similar to this) (im in physics and nt in calculus yet)

anonymous · Answer

is this really $V(t)=\cos(t^2-2)$??

anonymous · Answer

max is of course 1, because that is the maximum of cosine, and $\cos(0)=1$ so you would set $t^2-2=0$ and find that $t=\sqrt{2}$

anonymous · Answer

minimum value of cosine is -1 and $\cos(\pi)=-1$ so you would have to solve $t^2-2=\pi$

anonymous · Answer

i guess you get $t=\sqrt{\pi+2}$

anonymous · Answer

graph looks like this http://www.wolframalpha.com/input/?i=cos%28x^2-2%29

anonymous · Answer

are the minumum/max values the same as the minumum/max velocities?