Question

Question:

Answer 1

Solve the equation:
\[3^{2x} = 4^{2-x}\]

Answer 2

do you know logs ? hint : take ln of both sides

Answer 3

its
\[2x \ln 3 = (3-x)\ln4\]

Answer 4

good.. so you can solve it now dont you ?

Answer 5

(isolate x)

Answer 6

\[\frac{ 2x }{ 3-x } = \frac{ \ln4 }{ \ln3 }\]

Answer 7

you have to solve for x .. so you better isolate x than what you did

Answer 8

i.e.
\[\frac{ 2x }{ 3-x } = 0\]

Answer 9

\[2xln3=(3-x)\ln4\]
\[2xln3+xln4 = 3\ln4\]
\[x(2\ln3+\ln4) = 3\ln4\]
\[x=3\ln4/(2\ln3+\ln4)\]