A metal sheet is in the form of triangle XYZ ,WHERE XY=8.8meter.X(Y ANGLE)Z=64 degrees and Y(XANGLE)Z=41degrees 1)using a scale of 1cm to represent 1m,construct an accurate scale drawing of the metal sheet. A hole is to be drilled on the metal sheet at the point O which is equidistant from X,Y and Z. 2)on the same diagram,draw the locus which represents points inside the triangle which are equidistant from a)X and Y, b)Yand Z.
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To be equidistant from those points means the single point inside the triangle which is the same distance from X, Y, and Z.
is this ur problem u texted about?
yes yehi problem hai
i dont understand, cliff has already explained it what dont u understand?
well he has not explained it clearly..
can u understand hindi?
haan bolo
kya samajh nahin aaya
dude look after drawing angles n and side part one main they are saying that using a scale of 1cm a hole ids to be drilled on the metal sheet at point O which is equidistand from X y AND z..ab ye batao ke humey kya pata where is point O aur kahan per hole means cirlcle kis point per 1cm ka construct karna hai??
If you have straightedge and compass, you can experiment with your own drawing on paper. If you have protractor too, you can get the angles right. http://jwilson.coe.uga.edu/emat6680fa05/evans/assignment%204/assignment%204.htm
ok iam sending u a link plz just expalin me point 7 http://www.mathopenref.com/constincircle.html
The incenter is equidistant from the sides but is not equidistanct from the vertices.
u make two notches on the lines from the incentre. use these notches to make two new crossing notches draw a line from the crossing point to incentre thats ur perpendicular
ok thank u
you're welcome
First, can you draw the figure?
yes i have drawn the figure
but dont know wtha to do next
what*
You need to find the center of a circle that goes around the triangle The center is where the perpendicular bisectors of each side meet See http://www.mathopenref.com/constbisectline.html for how to bisect a line segment.
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