A. Graph y = x^3 – 2x^2 + 6. Describe what you see

Question

A.	Graph y = x^3 – 2x^2 + 6. Describe what you see

anonymous · Answer

Try plotting points. You can also plot y=x^3 first (the parent function) and then see how the additional terms change things.

anonymous · Answer

is this what i should i get ==> http://www.wolframalpha.com/input/?i=y+%3D+x3+%E2%80%93+2x2+%2B+6

anonymous · Answer

Yes, that is what it looks like. You should describe it in terms of end-point behavior (what is happening on the extreme left and extreme right sides. How many x-intercepts does it have and roughly where are they. Where is the y-intercept. How many turning points does it have, etc.

anonymous · Answer

so the answer could be 
The line starts at (1 , -1)  and travels up all the way to (6, 0) and slightly dropping to (1.5 , 5) and then quickly rising all the way up to (2 , 7) creating a snake like look to the line.

anonymous · Answer

@CliffSedge

anonymous · Answer

That's pretty good, but it doesn't start or end anywhere. It 'starts' from negative infinity and 'ends' at negative infinity, has an increasing portion, a turning point (local maximum), a decreasing portion to another turning point (local minimum) and then continues to increase without bound.
Otherwise, everything you said is fine.

anonymous · Answer

Are you able to estimate an x-intercept?

anonymous · Answer

yea some rough x - points would be -1.0 , 0 , 1.5 , 2

anonymous · Answer

@CliffSedge

anonymous · Answer

Sorry for the delay, getting ready to leave for work.
No, by x-intercept, I mean where does the graph cross the x-axis. What happens when y=0.
There appears to be an x-intercept near x = -1.3