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why does the integral of e^2x = (e^2x)/2?
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because of chain rule..
how's that go again?
e^2x >>> e^2x * d/dx of 2x? no
d/dx of 2x is 2 so how come e^2x >>>> 2 e^2x ??
You have to divide by the derivative of the inside function for integration. You multiply by the derivative of the inside function for differentiation.
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