Question

If volume of a sphere increases by 72.8% , how much percent does it's Surface Area increases ?? If volume of a sphere increases by 72.8% , how much percent does it's Surface Area increases ?? @Mathematics

Answer 1

well, the volume of a sphere is
\[V=\frac{4}{3}\pi r^3\]

the suface area is equal to
\[SA=4\pi r^2\]

start by determining how much r increases if you increase

so\[1.728\frac{4}{3}\pi r^3=\frac{4}{3}\pi R^3\]

and solve for R in terms of r

once you determine R in terms of r, substitute R into the SA equation

Answer 2

first thing is you need to find how much the radius changed
yeah thats exactly what i would say

Answer 3

for SA
\[(1+p)4 \pi r^{2} = 4 \pi R^{2}\]
you are solving for p, the percent increase in surface area