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Mathematics 18 Online
OpenStudy (anonymous):

expression for nth derivative of e^x^2

OpenStudy (anonymous):

Well, it's got e^x^2 in it......:-)

OpenStudy (anonymous):

\[e ^{x ^{2}}\]

OpenStudy (anonymous):

Then you have a polynomial multiplier

OpenStudy (anonymous):

2x,4x^2+1,8x^3+12x,16x^4+48x^2+12,32x^5+160x^3+120x.....

OpenStudy (dumbcow):

do the first 3 derivatives and see if you can spot a pattern \[f'(x) = 2x e^{x^{2}}\] \[f''(x) = (2x)^{2} e^{x^{2}} + 2e^{x^{2}}\] \[f'''(x) = (2x)^{3}e^{x^{2}} + 12x e^{x^{2}}\] \[\rightarrow f^{n} (x) = (2x)^{n} e^{x^{2}} + ...\]

OpenStudy (anonymous):

didn't spot, that's why ask, :)

OpenStudy (anonymous):

maybe i am dumb, but i don't get it @estudier

OpenStudy (anonymous):

Did you look up Hermite polynomials? http://en.wikipedia.org/wiki/Hermite_polynomials There is a table in the middle of the page seems very similar looking to sequence.....

OpenStudy (anonymous):

I have to find it without use of Hermite

OpenStudy (anonymous):

should be simple enough, :)

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