expression for nth derivative of e^x^2
Well, it's got e^x^2 in it......:-)
\[e ^{x ^{2}}\]
Then you have a polynomial multiplier
2x,4x^2+1,8x^3+12x,16x^4+48x^2+12,32x^5+160x^3+120x.....
do the first 3 derivatives and see if you can spot a pattern \[f'(x) = 2x e^{x^{2}}\] \[f''(x) = (2x)^{2} e^{x^{2}} + 2e^{x^{2}}\] \[f'''(x) = (2x)^{3}e^{x^{2}} + 12x e^{x^{2}}\] \[\rightarrow f^{n} (x) = (2x)^{n} e^{x^{2}} + ...\]
didn't spot, that's why ask, :)
maybe i am dumb, but i don't get it @estudier
Did you look up Hermite polynomials? http://en.wikipedia.org/wiki/Hermite_polynomials There is a table in the middle of the page seems very similar looking to sequence.....
I have to find it without use of Hermite
should be simple enough, :)
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