Find a cubic function with the given zeros. You must show your work for credit. -6, 5, -2 for a medal please
(x + 6)(x - 5)(x + 2)
easy
Thats it ?
yup
(x+6)(x-5)(x+2)
it is a cubic function that is zero at all the points listed
Yess ,
Is there any work to that i need it ?
No
If you want you can multiply it out so it isn't in factored form
Yeaa ,
sure can you put please
You do not have to do that though
Although if you do not know how to do that then you should probably learn
especially if you are in functions
Right You Can Just Do The First Part ,
so I would say for the cubic function with the given zeros you would have the given points (x+6)(x-5)(x+2) That would be my answer?
Right
Do you not understand how we got that answeR?
not really explain
(a+b)(c+d)(e+f) = ( a(c) + a(d) + b(c) + b(d) )(e+f) )
(a+b)(c+d)(e+f) = ( a(c) + a(d) + b(c) + b(d) )(e+f) )
Do Youu Get It
We know (x + 6) when x = -6 (-6 + 6) = 0 (x -5) when x = 5 (5 - 5) = 0 etc we know that a cubic function is a function that has x^3 thus if we multiply all three together we will get an x^3
This will give x^2 (x+3)(x+2) This will give x^3 (x + 6)(x - 5)(x + 2) this's will give x^4 (x+3)(x+4)(x+4)(x+4)
etc
When the only stipulation is that a function has an x to a specific degree and particular zeros you can just make up a factored form that has these traits vary easily
so hows this : for the cubic function with the given zeros you would have the given points (x+6)(x-5)(x+2)(x + 6) for a further example I know that x = -6 because(-6+6)=0 and also(x -5) x = 5 (5-5)=0 and furthermore you know that a this is a cubic function if it has x^3 and if I were to multiply them all I would get x^3 (x + 6)(x - 5)(x + 2)= x^3
Thats Correct
(x + 6)(x - 5)(x + 2) = (x^2 - 5x + 6x + 30)(x+2) = (x^2 + x + 30)(x+2) = x^3 + 2x^2 + x^2 + 2x + 30x + 60 = x^3 + 3x^2 + 32x + 60
Right ^
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