Compute the matrix of the partial derivative: f(x,y) = (e^x, sinxy)
Matrix ?? Only if it is second order. Otherwise just a 2-vector
so would i have to use the derivative as the second row? {e^x sinxy e^x ycosxy} ?
Ahh sorry u r right -
did i derive them correctly? that's usually where I start to mess up
It's a matric since u have TWO diffrent functions in the F
No - there must be on ZERO result because the first component e^x is independent of y
sorry, but I don't know what you mean. I am more of a visual learner. Could I use the Dot Product to solve this?
Yes - but "dot product " with a vector-differential operator
Nabla = (Dx, Dy)
Nabla?
Grad (more common in US)
gradient?
You see Grad is a notation for the operation. Gradient is the opertaion. Grad is the notation (like + is the notation for addition)
So anyways in ur matrix First Column = Grad (e^x), Second Column= Grad(sin xy)
so i should have grad = < e^x , xcos(xy) >?
Noo 1-st column is Grad(e^x) is A COLUMN of 2 derivatives i.e. Dx above Dy 2-nd column Grad(sin xy) ....
{e^x xcosxy 0 ycosxy} ? ( am I getting close at all? )
Yes u r there
Sorry, the second column is inverted in order
?
invert the order in the 2-nd column
i'm sorry, I don't quite know what you mean by 'invert.' do i switch them? or change them to negative?
@Mikael Sorry if I'm a but slow at this
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