Question

parametric plot of r(t) = (1+t, 3t, -t) ?

Answer 1

are you supposed to do it by hand somwhow?

Answer 2

somehow*

Answer 3

yes

Answer 4

I would find the vector then, and put this in vector form; that should make it more obvious

Answer 5

vector form of a line in R3 is
r(t)=(a,b,c)+t(x,y,z)
where (a,b,c) is the a point on the line and (x,y,z) is the direction vector

Answer 6

Are you supposed to tell what the graph of this is?

Answer 7

yeah

Answer 8

in your case it looks like you can use (a,b,c)=(1,0,0) and (x,y,z)=(1,3,-1)
that tells you this is a line

Answer 9

Okay.
So x = 1+t
y = 3t And z = -t
=> Equating the parameter,
y/3 = (x-1) = .-z

Answer 10

r(t)=(1,0,0)+t(1,3,-1)=(1+t,3t,-t)

Answer 11

What I need to do is to graph the vector in R3

Answer 12

the vector is (1,3,-1) so it is one in the +x, three in the +y, and 1 in the -z direction

Answer 13

Which as turningTest clearly said is the equation of a line Having direction ratio's
(3,1,-1)
And passing through 0,1,0

Answer 14

...passing through (1,0,0), but yeah...

Answer 15

Ohh yeah. My bad, 1,0,0 it is.

Answer 16

here are your axes with P=(1,0,0) labeled, now draw in the vector...

Answer 17

there are the vector components (the vector is not going to be easy to draw in 2D :/ )

Answer 18

something like that (pointing a bit down in the z)

Answer 19

extending it as a line would be likeor something....

Answer 20

wolfram's drawing is not much clearer...
http://www.wolframalpha.com/input/?i=parametric+plot+r%28t%29%3D%281-t%2C3t%2C-t%29

Answer 21

Thats really hard to draw.
You did it pretty damn well though.

Answer 22

thanks :)

Answer 23

Thank you very much!

Answer 24

welcome
I should note you also could have just picked two values for t, like t=1 and t=0, and plot those on the grid, then draw a line between them
good to know more than one way though ;)

Answer 25

(that would not work of each component was not linear though)

Answer 26

if*