–3x + 2y = 8 change to slope intercept form show all steps.
Slope intercept form is y=mx+b Step 1: Isolate the term with the y variable
2y=11
You can't combine 3x and 8 because 3x has a variable and 8 doesn't
ok so?
It will be 2y=3x+8, but you still have to remove the number attached to y by dividing both sides by that number
how do you do that
@hal_stirrup
can you help ?
Don't you know how to manipulate equations ?
no
then you should go back to basic equations and practice that so you can get this. dont build a house of card . solid maths foundation is key.
You need to divide both sides by 2 to remove the 2 that is with the y variable If it was a fraction, you would multiply by the denominator to cancel it out
For the other side, simply divide both terms by 2 to get your answer.
2y=3x+8 3x 4y ??
ok . lets say y/2=x solve for x? what operator do you need to use?
idkk :(
think about it.
divide?
divide what?
y and 2?
nop
dammit
ok if i say to you make y/2 to y what do you have to do. note that y/2 is really \[y\frac{ 1 }{ 2 }\]
darn idk
Sh!+
please go to this link http://www.khanacademy.org/math/algebra/solving-linear-equations-and-inequalities/v/simple-equations
its easy . trust me. ;)
Can you just please give me the answer? this is the last question.
no sorry NOT allowed . website rules.
rules are mint to be broken
JK
no not here and not for me.
Alright sounds like people are harsh over here. The slope formula is mx+b=y So thus you need to get the equation above like it.. -3x+2y=8 First, I would add 3x to both sides. So it's like 3x+(-3x) +2y = 8 -3x, the 3x's on the left will cancel. So you will get 2y = 8-3x. So now it's almost in the mx + b =y form you have have the extra 2 in the 2y So now you need to divide both equations by 2 to eliminate the 2y. Thus it would be like... 2y/2 = 8-3x/2 or you can write it like y = 8/2-3x/2... finally the 8/2 can be reduced to 4 SO finally the answer would be... y = 4 - 3/2x
actually time out let me fix that.. it won't be -3/2x it should be +3/2x it will actually be y = 4 + 3/2x
Thank you very much
You're welcome!
Join our real-time social learning platform and learn together with your friends!