Question

Differentiate the function.

Answer 1

\[\frac{ A }{ B + Ce^x }\]

Answer 2

\[\frac{ (B+Ce^x)(A) - (A)(B+Ce^x) }{ (B+Ce^x)^2 }\]

Answer 3

try rewriting as\[A(B+Ce^x)^{-1}\]and using the chain rule
... you forgot to take the derivative of \(A\), which is zero, in your attempt

Answer 4

you also did not take the derivative of \(B+Ce^x\)

Answer 5

\[(\frac uv)'={u'v-v'u\over v^2}\]

Answer 6

\[\frac{ (B+Ce^x)(1) - (A)((1) + Ce^x)) }{ (B+Ce^x)^2 }\]

Answer 7

why is the deriv of A , 0?

Answer 8

is A a constant?

Answer 9

A is a constant?

Answer 10

I don't know, what are you taking the derivative with respect to?

Answer 11

its just a random problem, are A B and C usually constants? because i always treat them as variables

Answer 12

well you can only take the derivative with respect to one variable at a time
if A was a function of x the derivative would still not be one
d/dx(A(x))=A'(x) not 1
however I think it is safe to assume that A, B, and C are constants, and that you are taking the derivative wrt x

Answer 13

ahhh ok thank you!!

Answer 14

welcome!