Physics Help!!! Your car tire has a diameter of 3m and is rotating at 4 rev/s, when suddenly Bob slams his foot down on the accelerator. After traveling 400 m, the tire's rotation has increased to 10 rev/s. What was the tire's angular acceleration?
I know the formula for angular acceleration is this: \[\alpha=\frac{ d \omega }{ dt }\]
Well, try this formula: w^2=w_0^2+2*al*th you can find th first by finding how many revolution the tire made in 400 m (if it's diameter is 3 m). Then you can substitute this to the first formula for al. Hope this help :D read: w=\omega; al=\alpha; th=\theta; sorry for this :)
So the formula is: \[w^2=w_0^2+2*al*th\] What's the theta? I mean, what would I plug in for the theta. So, the alpha would be equal to 40... Is that right?
According to the unit used in the problem, you can substitute theta with number of revolution (I stated this before, right?).
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