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Mathematics 7 Online
OpenStudy (anonymous):

suppose you know that \[\sqrt[n]{a/b}\] is a rational number and that "a" and "b" have no common factors. What can you say about the prime factorizations of "a" and "b"?

OpenStudy (anonymous):

must be perfect squares

OpenStudy (anonymous):

but n could be something else sqrt[n]{a/b} = \[\sqrt[n]{a/b}\]

OpenStudy (anonymous):

then replace "square" by \(nth\)

OpenStudy (anonymous):

ok, thanks

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