Question

How do you graph x = 2y^2 - 3?, and give the
Domain (x) and Range (y)

Answer 1

solve for y

Answer 2

yea

Answer 3

then move your vertex

Answer 4

I mean I haven't graphed it yet and needed to be y =

Answer 5

How would I graph it the way it is or is it possible

Answer 6

ok tell me what you go when you solved for y. y= and some equation right?

Answer 7

like explain it to you

Answer 8

yeah tell me your new equation

Answer 9

that's what I need help on actually

Answer 10

just reverse you pemdas.

Answer 11

how would I do that

Answer 12

add 3 to both sides first, divide both sides by 2 and square root both sides

Answer 13

I think it's wrong, but I got: y = 3x + 2^2

Answer 14

no. \[\sqrt{\frac{ x+3 }{ 2}}=y\]

Answer 15

y = mx + b

Answer 16

write it out like that

Answer 17

yu cant because yur line above has the x and y on the opposite sides. was it suppose to be that way?

Answer 18

It has to be written out y intercept form

Answer 19

then i cant help yu ther because i dont think it can.

Answer 20

alryte sir

Answer 21

awesome

Answer 22

to graph this the first thing would be to set it to y= format

Answer 23

yep I got that it's just how to I forgot to do that

Answer 24

whenever I get into y = form I am good

Answer 25

herewego pretty much got it with \[y=\pm \sqrt{\frac{ x+3 }{ 2 }}\]

Answer 26

did you subtract 3 to both sides

Answer 27

no i just rearranged it so that 2y^2 was by itself

Answer 28

was that the answer

Answer 29

so what's the answer

Answer 30

to find the domain would be \[\frac{ x+3 }{ 2 }\ge 0\]

Answer 31

well domain (x) is -2, -1, 0, 1, 2

Answer 32

I just need range (y)

Answer 33

http://www.wolframalpha.com/input/?i=graph+sqrt%28%28x%2B3%29%2F2%29

Answer 34

range is your y values so it appears to be 0 to infinity

Answer 35

so would it be 0 for all y values

Answer 36

uh correct

Answer 37

\[[0,\infty)\]

Answer 38

is that it

Answer 39

uh???

Answer 40

ya

Answer 41

why nick???

Answer 42

well the y value starts at 0 and goes off to infinity

Answer 43

is it a function

Answer 44

im basing it off the graph i sent the link

Answer 45

At least it's right