Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

tan^2(2+3a)

OpenStudy (anonymous):

derivative

OpenStudy (anonymous):

this mite help http://www.wolframalpha.com/input/?i=tan^2%282%2B3a%29

OpenStudy (anonymous):

thanks

OpenStudy (anonymous):

did it hep

OpenStudy (anonymous):

help lol

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

thanks C=

OpenStudy (anonymous):

hi miles did you try the chain rule?

OpenStudy (anonymous):

whats that

OpenStudy (anonymous):

well in differentiation there are rules to help us to differentiates problem like this one

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

to solve this one you have to use the chain rule...

OpenStudy (anonymous):

ok how

OpenStudy (anonymous):

ok lets try this one..if we let y=tan^2(2+3a) and we want the derivative of y with respect to a, we will have.... dy^2/da=2y dyda

OpenStudy (anonymous):

substituting y(a)=tan^2(2+3a) from dy^2/da=2y dyda we get dy^2/da=2tan(2+3a)sec^2(2+3a)*3=6tan(2+3a)sec^2(2+3a)

OpenStudy (anonymous):

did you get it?

OpenStudy (anonymous):

yes i think

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!