Question

Solve for x:
[2(a-x)/3cube root of x]-x^2/3=0

Answer 1

\[\frac{ 2(a-x) }{3\sqrt[3]{x} }-x ^{2/3}=0\]
So this is basically what equation look like, and solve for x

Answer 2

try multiplying EVERYTHING by \(\large \sqrt[3]x\)

Answer 3

Sorry, I'm kinda stuck there. I'm try think, but what do I get by multiplying everything by \[\sqrt[3]{x}\]

Answer 4

hmm sorry...i got confused now too

Answer 5

i know...LCD
\[\huge \implies \frac{2(a-x)}{3\sqrt[3] x} - \frac{3x}{\sqrt[3]x} = 0\]

Answer 6

the denominator of the fraction should have a3

Answer 7

\[\huge \frac{2(a-x)}{3\sqrt[3]x} - \frac{3x}{3\sqrt[3]x} = 0\]

Answer 8

yeah, I got to that first part.

Answer 9

now combine them
\[\huge \implies \frac{2(a-x) -3x}{3\sqrt[3]x} = 0\]
now...cross multiply..what do you get?

Answer 10

2a-5x=0

Answer 11

right

Answer 12

so solve for x

Answer 13

2a/5

Answer 14

right

Answer 15

so x = 2a/5

Answer 16

ok, awesome...thanks

Answer 17

welcome