2 The sum of a number and its reciprocal is 51. Find the number.
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OpenStudy (tyteen4a03):
The equation you're looking for is x + (1/x) = 51.
OpenStudy (jiteshmeghwal9):
Let the number be 'x'.then,
its reciprocal=\(\Large{1 \over x}\)
A/q,
\(\Large{\implies {{x+{1\over x}={51}}}}\)
\(\Large{\implies{{x^2+1\over x}=51}}\)
OpenStudy (jiteshmeghwal9):
i think u can do this now :)
OpenStudy (anonymous):
hmm I made it to x^2-51x+1=0 but whats the next step?
OpenStudy (jiteshmeghwal9):
u can solve this quadratic equation by either quadratic formula method or factorization method if possible.
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OpenStudy (jiteshmeghwal9):
so after looking @ the equation we see that it can't be done by factorization method
OpenStudy (jiteshmeghwal9):
hence, we use quadratic formula method
OpenStudy (anonymous):
Can you help me check if the answer is x = 2.6180339887499 ?
OpenStudy (tyteen4a03):
I got 50.9804. The exact form is x = 2/(51+7 sqrt(53))
OpenStudy (anonymous):
hmm what if the recipicol is 5 and 1/5?
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