Find the set of values of p such that px^2+2x+4p < 0 for all x.
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OpenStudy (anonymous):
if this is true for all x then its D <0
OpenStudy (anonymous):
Sorry, if i could get some working. I would appreciate it.
OpenStudy (anonymous):
|dw:1347355945880:dw|
OpenStudy (anonymous):
does it make sense?
OpenStudy (anonymous):
y= px^2+2x+4p and y<0 for all x
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OpenStudy (anonymous):
Sorry, i have no idea where you are coming from?
OpenStudy (anonymous):
ok...u have written some quadratic expression...px^2+2x+4p...right?
OpenStudy (anonymous):
Its under the chapter of quadratics. And yes i have written that.
OpenStudy (anonymous):
u know that curve of a quadratic is a parabola?
OpenStudy (anonymous):
Assume all medium levels of knowledge.
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OpenStudy (anonymous):
ok....
OpenStudy (anonymous):
Im from australia and here i do the highest level of maths for my respective grade, 11.
OpenStudy (anonymous):
ok
OpenStudy (anonymous):
how many roots a quadratic equation has?
OpenStudy (anonymous):
ok....let's draw the curve y = x^2 +3x+4
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OpenStudy (anonymous):
are you comfortable with this?
OpenStudy (anonymous):
Yes, I can understand that much. I'm the one in the class who always wants to know why. Why do we remove the p for now? Sorry if its a simple question, i just want to be able to repeat this to someone else if they ask.
OpenStudy (anonymous):
i am not saying that it's a simple question...and simplicity depends on whether one knows or not? even if I had not known to solve this then it wud have been a difficult question for me
OpenStudy (anonymous):
let's draw the curve y = x^2 +3x+4
OpenStudy (anonymous):
So we remove the pronumeral which they wish us to find?
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OpenStudy (anonymous):
we draw the curve y = x^2 +3x+4
OpenStudy (anonymous):
Do you mean y=x^2+2x+4?
OpenStudy (anonymous):
still there?
OpenStudy (anonymous):
Yes. Im here and willing to listen.
OpenStudy (anonymous):
isolate the terms with 'p'
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OpenStudy (anonymous):
factor out p
OpenStudy (anonymous):
divide both sides by the factor of p (it will be negative so the <> sign must reverse)
OpenStudy (anonymous):
p< -2x/(x^2+4)
OpenStudy (anonymous):
Im with you.
OpenStudy (anonymous):
check the range of -2x/(x^2+4) to find allowed values for p
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OpenStudy (anonymous):
Range as in Domain and Range?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
In terms of x or p?
OpenStudy (anonymous):
-2x/(x^2+4) has an absolute min
OpenStudy (anonymous):
if you're not doing calc. yet... hmm.
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OpenStudy (anonymous):
are you?
OpenStudy (anonymous):
No I am doing calc.
OpenStudy (anonymous):
ah easy then
OpenStudy (anonymous):
find the min of -2x/(x^2+4)
OpenStudy (anonymous):
p is any value less than that min
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OpenStudy (anonymous):
Its in a quadratic section though, so I would prefer not to use calc.
OpenStudy (anonymous):
hmm yeah I think you can use the vertex form that someone mentioned briefly before deleting the comment to do it a different way...