Find the inverse function f(x)=e^(2x-1)
let y = e^(2x-1) now express x in terms of y. can u? then just replace y with x.
how do you express x in terms of y on this one
@hartnn the math lover....are inverse functions expressed as y = ?
take natural log on both sides. ln y = ln (e^(2x-1))
now what hart
u know the property of log, ln a^b = b ln a ??
@lgbasallote this is how they teach us, to replace the f(x) with y then solve for x, then switch them when done
this is why i hate math...too many rules
im rusty with logs hartnn
if u know then ln(e^(2x-1)) = (2x-1) ln e and ln of e =1 because the base of ln is also e.
so u have ln y = 2x-1 now can u find x in terms of y ??
i will explain let f(x)=y then, y= e^(2x-1), the most important thing is inverse function is symmetry to y=x so you can replace y to the x and x to the y so given funtion is arraged by x=e^(2y-1) by the rule y=e^x <=> lny=x lnx=2y-1 so answer is (lnx + 1)/2 = y
perfect thanks guys
ok, welcome :)
ok, welcome :)
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