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OpenStudy (anonymous):

What are the assumptions for free-fall problems?

OpenStudy (anonymous):

do u have any idea about assumptions?

OpenStudy (anonymous):

I think so..

OpenStudy (anonymous):

I mean I know that when an object is dropped from a height you assume its initial velocity as 0.

OpenStudy (anonymous):

so tell...what do we assume in free-fall problems?

OpenStudy (anonymous):

that's all I know for now.

OpenStudy (anonymous):

it's an assumption?...u just release the object then it implies that speed of object is zero...

OpenStudy (anonymous):

suppose u throw the object vertically upward with a velocity....

OpenStudy (anonymous):

does it reach a peak and go down? or it just goes then down..

OpenStudy (anonymous):

it'll reach a peak and at the peak speed of object will be zero and then it'll starts to fall down

OpenStudy (anonymous):

these are not assumptions of free fall...

OpenStudy (anonymous):

1st tell me..what is free fall?

OpenStudy (anonymous):

what are they called then?

OpenStudy (anonymous):

http://www.frigginphysics.com/2011/01/the-physics-of-free-falling-bodies/ in this site it says it is....

OpenStudy (anonymous):

free fall: experiences a downward acceleration of 9.8m/s/s

OpenStudy (anonymous):

yes...:)

OpenStudy (anonymous):

have you seen the site?

OpenStudy (anonymous):

suppose when i throw an object upward then what will be the acceleration?

OpenStudy (anonymous):

here it's written...What Your Physics Textbook Assumes You Know.. it doesnt mean that these are the assumptions of free fall

OpenStudy (anonymous):

yes...when we solve problems of free fall or we use kinematic equations...we make some assumptions..

OpenStudy (anonymous):

like air resistance is zero...acceleration due to gravity is constant throughout the motion

OpenStudy (anonymous):

the a upward would be -9.8m/s/s ?

OpenStudy (anonymous):

now tell me...what do u mean by acceleration due to gravity?

OpenStudy (anonymous):

also why is it -9.8m/s/s downwards? and my teacher says that it's also -9/8m/s/s upwards?

OpenStudy (anonymous):

I just don't get that....

OpenStudy (anonymous):

just wait...there r some misconceptions..where r u from?

OpenStudy (anonymous):

Philippines.... sadly.

OpenStudy (anonymous):

Whether the object is falling downward or rising upward towards its peak, if it is under the sole influence of gravity, then its acceleration value is 9.8 m/s/s.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

contradicts with this statement An object in free fall experiences an acceleration of -9.8 m/s/s. (The - sign indicates a downward acceleration.) Whether explicitly stated or not, the value of the acceleration in the kinematic equations is -9.8 m/s/s for any freely falling object.

OpenStudy (anonymous):

it says in the first statment: 9.8m/s/s but in the second it says -9/8m/s/s....

OpenStudy (anonymous):

i don't get it

OpenStudy (anonymous):

wow....u have struggled a lot...great!

OpenStudy (anonymous):

tbh, I can't do it anymore, super failing in physics...

OpenStudy (anonymous):

let's start...as i asked...what's acceleration due to gravity?

OpenStudy (anonymous):

Earth pulls every object towards itself with acceleration of 9.8 m/s/s

OpenStudy (anonymous):

right?

OpenStudy (anonymous):

yes. okay.

OpenStudy (anonymous):

acceleration due to gravity is a vector quantity?

OpenStudy (anonymous):

yes.

OpenStudy (anonymous):

so it should have magnitude along with direction?

OpenStudy (anonymous):

yes. .

OpenStudy (anonymous):

so magnitude of acceleration due to gravity= 9.8m/s/s

OpenStudy (anonymous):

okay.

OpenStudy (anonymous):

there is no + or - with the magnitude of any vector quantity

OpenStudy (anonymous):

why is that? isn't it that if the direction is eastward its + and the direction westward is - ?

OpenStudy (anonymous):

now we take a problem|dw:1347363469872:dw|

OpenStudy (anonymous):

just wait...we will discuss them later

OpenStudy (anonymous):

now we concentrate on the above problem

OpenStudy (anonymous):

I cannot comprehend your diagram..

OpenStudy (anonymous):

I'll explain...|dw:1347363673740:dw|

OpenStudy (anonymous):

it's fine?

OpenStudy (anonymous):

okay. :)

OpenStudy (anonymous):

what's u?

OpenStudy (anonymous):

thank you demitris. :D

OpenStudy (anonymous):

now we have to calculate after what time it'll reach the peak?

OpenStudy (anonymous):

and for doing any measurement, we need frame of reference.

OpenStudy (anonymous):

wait... a min

OpenStudy (anonymous):

when our teacher discussed kinematics and free fall he did not talk about frame reference, he will talk about it sometime this month but we are now starting a new term.....

OpenStudy (anonymous):

just wait...i'll come to your questions..

OpenStudy (anonymous):

let me tell what do I mean my some reference for doing the measurement

OpenStudy (anonymous):

alright :D

OpenStudy (anonymous):

|dw:1347364018900:dw|

OpenStudy (anonymous):

alright

OpenStudy (anonymous):

|dw:1347364108989:dw|

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