Question

sin h 3x e^4x
find the nth derivative

Answer 1

Is that:
\[sinh{3x} \cdot e^{4x}\]
?

Answer 2

what to do with that?

Answer 3

if the eq is like traxter wrote, the exchange sinh(3x) as a exp function.

Answer 4

hello

Answer 5

sin h 3x e^4x
find the nth derivative

Answer 6

can u find the n th derivative of e^{ax} ?

Answer 7

sin h 3x e^4x
find the nth derivative will u derive it

Answer 8

can u find the n th derivative of e^{ax} ?
form:a^n e^ax

Answer 9

e^ax nth derivative is (a^n)e^ax

Answer 10

maybe it is easy to change sinh3x in a exp function

Answer 11

Leibniz' theorem/ binomial stuff will work for u\[(uv)^{(n)}=\sum_{k=0}^{n}\left(\begin{matrix}n\\k\end{matrix}\right)u^{(n-k)}v^k\]

Answer 12

sinh3x = (e^3x - e^-3x)/2

Answer 13

so the given eq is ruduced as (e^7x - e^x)/2

Answer 14

then you apply a e^ax derivative rule

Answer 15

can u explain breifly plz

Answer 16

then the answer is [(7^n)e^7x - e^x]/2

Answer 17

the definition of the sinhx = (e^x - e^-x)/2. we promised it

Answer 18

ignore my comment

Answer 19

@shambavi ask if u still don't get it.

Answer 20

@LeeYeongKyu heyy thankxxxx i got it

Answer 21

if you want to know why sinhx = (e^x - e^-x)/2 use euler theory