Question

Differentiate the function.

Answer 1

\[y=\frac{ xsinx }{ 1+x }\]

Answer 2

\[y'=\frac{ (1+x)(xsinx)' - (xsinx)(1+x)' }{ (1+x)^2 }\]

Answer 3

i get the wrong anser here

Answer 4

\[\frac{ (1+x)(xcosx)-(xsinx)(1) }{ (1+x)^2 }\]

Answer 5

(1+x)' = 1
i think u are sure about this...
u need to use fg'+f'g in x cos x

Answer 6

the book has a + sinx with that xcosx

Answer 7

by taking f as x and g as cos x

Answer 8

x*cos(x) + sin(x) =(x*sin(x)) '

Answer 9

product rule

Answer 10

so, its possible to use the product rule, inside of the quotient rule

Answer 11

not possible, necessary.

Answer 12

required, in fact. :)

Answer 13

ok, so let me see if I set this up correctly

Answer 14

\[y = \frac{ xcosx + sinx + x ^{2}cosx }{ (1+x)^{2} }\]

Answer 15

\[y'=\frac{ (1+x)(x(sinx)') + (sinx(x)') - (xsinx)(1+x) }{ (1+x)^2 }\]

Answer 16

pretty much... you left off a prime on that last (1+x) ...other than that good.

Answer 17

wow that really cleared it up for me, thanks @Algebraic!

Answer 18

I'm glad:)

Answer 19

yw