Question

solve 2y/y+1=2-8/2y

Answer 1

\[\frac{ 2y }{ y+1 }=\frac{ 2-8 }{ 2y }\]

Answer 2

\[2y(2y)=(y+1)(2-8)\]
thats after cross multiplying

Answer 3

see what happened?

Answer 4

?

Answer 5

ok now we want to keep the 4y^2 on the left so it stays positive and move the - 6y and - 6 over to the left by adding them to both sides setting the equation = to 0

Answer 6

you are going to have to use the quadratic equation which is
\[\frac{ -b \pm \sqrt{b^2 - 4(a)(c)} }{ 2a }\]

Answer 7

in your eqaution, 4 = a, 6 = b and 6 = c

Answer 8

ax^2 + bx + c

Answer 9

\[\frac{ -6\pm \sqrt{6^2 - 4(4)(6)} }{ 2(4) }\]

Answer 10

thats what i wanted you to do

Answer 11

what are you left with

Answer 12

you there?